i think answer is (2)
((R ∨ Q) ∧ (P ∨ ¬Q) ∧ (R ∨ P))
R ∨ Q
P ∨ ¬Q
R ∨ P
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cancel the Q and ¬Q only remain (R ∨ P) ∧ (R ∨ P)
(R ∨ P) result 1
for
((R ∨ Q) ∧ (P ∨ ¬Q))
(R ∨ Q)
(P ∨ ¬Q)
-------------------
cancel the Q and ¬Q
you will get R ∨ P which is similar to result 1