Register

number of solutions

254 views
1 votes
1 votes
When we find rank(A) and rank(AB)

what are the cases to get

1.no solution

2.unique solution

3.infinite solution

4.more than one solution
User Avatar

Please log in or register to answer this question.

Voting & Accepting an answer helps improve the community
← PreviousNext →
← Previous in categoryNext in category →

Related questions

0 votes
0 votes
0 answers
1
A_i_$_h asked Nov 27, 2017
311 views
number of solutions
Consider the following system of equations: 3x+2y=13x+2y=1 4x+7z=14x+7z=1 x+y+z=3x+y+z=3 x−2y+7z=0x−2y+7z=0 The number of solutions for this system is ______________ For such questions The number of solutions can be classified only into 3 types right? 1.unique 2.infinite 3.no solution
Consider the following system of equations: 3x+2y=13x+2y=14x+7z=14x+7z=1x+y+z=3x+y+z=3x−2y+7z=0x−2y+7z=0The number of solutions for this system is ______________ For...
User Avatar
2 votes
2 votes
3 answers
2
A_i_$_h asked Oct 9, 2017
2,540 views
number of solutions
Number of non negative integer solutions such that $x + y + z = 17$ where $x>1,\ y>2,\ z>3$
Number of non negative integer solutions such that $x + y + z = 17$ where $x>1,\ y>2,\ z>3$
User Avatar
0 votes
0 votes
0 answers
4
Lakshman Bhaiya asked Oct 24, 2018
390 views
Number of solutions
Suppose that a solution $(X,Y,Z)$ of the equation $X+Y+Z=20,$with $X,Y$ and $Z$ non-negative integers, is chosen at random.What is the probability that $X$ is divisible by $5?$ $A)\frac{1}{4}$ $B)\frac{5}{21}$ $C)\frac{2}{7}$ $D)\frac{3}{20}$
Suppose that a solution $(X,Y,Z)$ of the equation $X+Y+Z=20,$with $X,Y$ and $Z$ non-negative integers,is chosen at random.What is the probability that $X$ is divisible by...
User Avatar
Link Copied!