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This is an UP counter, counting starts from 000( as counter is initially reset) and increments by 1 on each pulse.

Q3Q2Q1Q0

0    0   0   0

when the outputs of Q2 and Q3 are 1 then NAND gate will produce o/p as 0 and it will clear all the flip flops.

Hence, answer will be mod 12 machine (0-11).

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