8,372 views
1 votes
1 votes
i m getting 16 but the answer is 17 .please explain

2 Answers

Best answer
6 votes
6 votes
for 8*256 decoder 1 would required in first level and 16 in second level  ....the best way to apprach this question is starting from 2nd level see 256 output lines so 256/16 decoder now to select one of 16 decoder we neead one 4:16 decoder so ans is 1+16=17
0 votes
0 votes

pls have a look at

similarly in your question,one 4;16 decoder will be used to select the one of 16 decoder in second level 

Related questions

6 votes
6 votes
3 answers
1
GateAspirant999 asked Oct 11, 2016
9,541 views
The truth table for the combinational circuit is shown below:What is the minimum number of two input NAND gates required to realize this logic circuit?
0 votes
0 votes
2 answers
2
0 votes
0 votes
1 answer
3
aoao asked Sep 26, 2018
2,428 views
The Answer is 3. But I think only 2 are required as R2 is many(E3) to one(E1) with total participation.Thus tables formed E2R1(DFA) with pk as DA. R2(GHABC) with pk as G....
1 votes
1 votes
1 answer
4