25 votes 25 votes What is the minimal form of the Karnaugh map shown below? Assume that $X$ denotes a don’t care term $\bar{b} \bar{d}$ $ \bar { b } \bar { d } + \bar{b} \bar{c} $ $ \bar{b} \bar{d} + {a} \bar{b} \bar{c} {d}$ $ \bar{b} \bar{d} + \bar{b} \bar{c} + \bar{c} \bar{d} $ Digital Logic gatecse-2012 digital-logic k-map easy + – Arjun asked Sep 25, 2014 edited Apr 25, 2019 by Sukanya Das Arjun 6.2k views answer comment Share Follow See 1 comment See all 1 1 comment reply palashbehra5 commented Nov 22, 2021 reply Follow Share 2 quads → 4 literals. 2 votes 2 votes Please log in or register to add a comment.
Best answer 36 votes 36 votes $2$ quads are getting formed. Value for First one is $b'd'$ and value for $2^{nd}$ one is $b'c'$. So, answer is option B. GATE_2016 answered Nov 4, 2015 edited Apr 25, 2019 by Sukanya Das GATE_2016 comment Share Follow See 1 comment See all 1 1 comment reply Ayush Upadhyaya commented Jan 7, 2019 reply Follow Share and those fully cover all minterm and they are also the essential PI. 2 votes 2 votes Please log in or register to add a comment.
16 votes 16 votes Care for $1$'s; not for don't cares answer = option B amarVashishth answered Oct 21, 2015 amarVashishth comment Share Follow See all 0 reply Please log in or register to add a comment.
2 votes 2 votes 2 quads are getting formed which is b'd'+c'b' Bhagirathi answered Sep 25, 2014 Bhagirathi comment Share Follow See all 0 reply Please log in or register to add a comment.
2 votes 2 votes In dont cares we prioritize as...octacts< quads< dia so ans is B Hirva Mehta answered Oct 1, 2015 Hirva Mehta comment Share Follow See 1 comment See all 1 1 comment reply Sona Barman commented Jul 17, 2019 reply Follow Share Can explain more then it would easy to understand.. 0 votes 0 votes Please log in or register to add a comment.