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What is the minimal form of the Karnaugh map shown below? Assume that X denotes a don’t care term

1. $\bar{b} \bar{d}$
2. $\bar { b } \bar { d } + \bar{b} \bar{c}$
3. $\bar{b} \bar{d} + {a} \bar{b} \bar{c} {d}$
4. $\bar{b} \bar{d} + \bar{b} \bar{c} + \bar{c} \bar{d}$
edited | 1.4k views

$2$ quads are getting formed.
Value for First one is $b'd'$ and value for $2^{nd}$ one is $b'c'$. So, answer is option B.

edited

Care for $1$'s; not for don't cares

+1 vote
2 quads are getting formed which is b'd'+c'b'
+1 vote

In dont cares we prioritize as...octacts< quads< dia

so ans is B

+1 vote
b'd' + b'c' option B

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