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What is the minimal form of the Karnaugh map shown below? Assume that $X$ denotes a don’t care term

 

  1. $\bar{b} \bar{d}$
  2. $ \bar { b } \bar { d } + \bar{b} \bar{c} $
  3. $ \bar{b} \bar{d} + {a} \bar{b} \bar{c} {d}$
  4. $ \bar{b} \bar{d} + \bar{b} \bar{c} + \bar{c} \bar{d} $
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5 Answers

Best answer
36 votes
36 votes

$2$ quads are getting formed.
Value for First one is $b'd'$ and value for $2^{nd}$ one is $b'c'$. So, answer is option B.

edited by
2 votes
2 votes

In dont cares we prioritize as...octacts< quads< dia

so ans is B

Answer:

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