# GATE2012-30

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What is the minimal form of the Karnaugh map shown below? Assume that $X$ denotes a don’t care term 1. $\bar{b} \bar{d}$
2. $\bar { b } \bar { d } + \bar{b} \bar{c}$
3. $\bar{b} \bar{d} + {a} \bar{b} \bar{c} {d}$
4. $\bar{b} \bar{d} + \bar{b} \bar{c} + \bar{c} \bar{d}$

edited $2$ quads are getting formed.
Value for First one is $b'd'$ and value for $2^{nd}$ one is $b'c'$. So, answer is option B.

edited
1
and those fully cover all minterm and they are also the essential PI.

Care for $1$'s; not for don't cares 2 quads are getting formed which is b'd'+c'b'
b'd' + b'c' option B
1 vote In dont cares we prioritize as...octacts< quads< dia

so ans is B

0
Can explain more then it would easy to understand..

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