Synchronous transmission

Question

In synchronous transmission, 5 eight bit characters are included in 30 eight bit information characters. If bit rate of sender is 4200 bps, what is the bit rate of receiver ?

Comments

@joshi_nitish, Just tell me one thing, sync bits are only sent during the start of the transmission and then all data is sent continuously right ?

---

no, this is not the case, sync bits are send at the start of every block of data, here one block = 30*8 bits..

---

@joshi_nitish there is a similar gate question. Check that.

Answer 1

Total bits in character$s$ = 280 bits.

280 bits makes 30 chars transferable units. 1 transferable char unit would contain 28/3 bits.  Therefore Receiver bit rate which is equal to transfer rate = 4200*3/28 = 450bps.

Comments

They have mentioned that 5 eight bit characters are include in 30 eight bit information i.e.
40 bit characters are already included in 240 bit info.

1 char size= 240/40
Transfer Rate = 4200*40/240 = 700
Then bit rate of receiver = 4200-700=3500bps

 

If they have mentioned that 5 eight bit characters are followed by 30 eight bit information i.e.
40 bit characters + 240 bit info. = 280

1 char size = 280/30

Transfer Rate = 4200*30/280 = 450
Then bit rate of receiver = 4200-450=3750bps

 

Is this right?

Answer 2

5 eight bit synch characters for 30 8 bit info characters, sync characters are not taken by receiver , they are send by sender just to inform receiver that data is coming.

5*8 = 40 bits (sync char bits)

30*8= 240 info bits

40 sync bits for 240 info bits,

then

for 4200 bits, (4200/240)*40 = 700 bits(sync bits)

sync bits are not needed, hence subtracting from 4200, 4200-700 = 3500 bits/s