2 votes 2 votes Is every Bounded lattice Complete ? Eg : ( { x : 0<=x<= 1} , <= ) This lattice is bounded , but is it complete ? (I have a doubt ; what if we consider irrational no.s as well) Set Theory & Algebra set-theory&algebra + – VS asked Oct 22, 2017 VS 991 views answer comment Share Follow See all 4 Comments See all 4 4 Comments reply srestha commented Oct 22, 2017 reply Follow Share A poset is called a complete lattice if all its subsets have both a join and a meet. In particular, every complete lattice is a bounded lattice but not vice versa See we can apply it for any number as we can take p,q,r as elements of lattice Now take p,q, r value as complex. irrational anything But ans not change 0 votes 0 votes VS commented Oct 23, 2017 reply Follow Share @srestha mam . . U mean to say that suppose complex no.s are incomparable so they main not have a join or a meet 0 votes 0 votes srestha commented Oct 23, 2017 reply Follow Share @VS Complex number are not incomparable always I think need not to research more on this As complex number lattice will not come in GATE 0 votes 0 votes VS commented Oct 23, 2017 reply Follow Share @srestha mam Thanks 0 votes 0 votes Please log in or register to add a comment.