1 votes 1 votes Operating System paging + – rohit vishkarma asked Oct 27, 2017 rohit vishkarma 259 views answer comment Share Follow See all 4 Comments See all 4 4 Comments reply Anu007 commented Oct 27, 2017 reply Follow Share Virtual address space divide like = 13 bits - 14 bits - 12 bits Physical address space divide like = 15 bits - 12 bits Page table size = number of entries * PTE size For outer : Number of entries are = 213 PTE size = 32 bits = 4B outer Page table size = 213*4B = 32 KB For inner = 214*8B = 128 KB 0 votes 0 votes A_i_$_h commented Oct 27, 2017 reply Follow Share @anu outer page table size is number of pages * PTE...got it :) but how did u take values for inner page table size 0 votes 0 votes rohit vishkarma commented Oct 30, 2017 reply Follow Share how are you getting these address... 0 votes 0 votes A_i_$_h commented Oct 31, 2017 reply Follow Share @rohit Page table size = number of pages * PTE size number of pages = 8 k = 213 PTE for outer table = 32 bits i think this is the way...am nt sure how @anu found the inner table size and also these statements Virtual address space divide like = 13 bits - 14 bits - 12 bits Physical address space divide like = 15 bits - 12 bits 0 votes 0 votes Please log in or register to add a comment.