In serial communication employing $8$ data bits, a parity bit and $2$ stop bits, the minimum band rate required to sustain a transfer rate of $300$ characters per second is
Since stop bit is given it is asynchronous communication and $1$ start bit is implied. So,
$\text{(8 + 2 + 1 + 1) * 300 = 3600 bps}$
Minimum band rate required would be $4800$ here.
How 4800 is coming?
why we are multiplying (300 characters/sec) with the bits..i am not getting dimensionally..?
@Arjun Please highlight, in your answer, why $4800$ is chosen when the actual answer comes out to be $3600$. This point is evident when going through the comments above, but in GO PDF, it is really very confusing to comprehend.
Transfer rate = Baud rate * (data bits/total bits)
300 * 8 = B * (8/12)
B = 3600
2400 < 3600 < 4800
4800 baud.