#number representation

Question

If we convert an n-digit number with base -2^k into base-2,the resulting number of digits will be of what order?

Comments

in base-2 it will contain nk digits

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how?? elaborate

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@shefali1 you can take the example of Octal number system(2³) and hexadecimal number system(2⁴) both have 3 and 4 bits in binary.

Answer 1

let n digit number be 123 and k=3 so base is 2$^{3}$=8, (723)$_{8}$ convert it in base 2 it will be (111010011) $_{2}$

n*k= 9 so the number of digit are also 9