$101$ hrs = $96+5$ hrs
$\qquad \qquad = 4 \hspace{0.1cm} day\hspace{0.1cm} 5\hspace{0.1cm} hrs$ $[∵ 96\hspace{0.1cm} hrs = 24 \times 4\hspace{0.1cm} hrs = 4 \hspace{0.1cm} days]$
∴ If the time is now $4'o \hspace{0.1cm} clock$
so after $101\hspace{0.1cm} hrs$ i.e. $4 \hspace{0.1cm}days$ & $5\hspace{0.1cm} hrs$, the time should be $9'o \hspace{0.1cm} clock$