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In greedy search, we expand the node that is estimated to be closest to goal.

Here, we see that at each level, we have b nodes to choose from (since branching factor is b) and there are m such levels at max.

∴∴ The total no. of nodes to choose from = b×b×b×…m times=b^m

∴∴ Space complexity = O(b^m)

Hence option A is correct.
 

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