In greedy search, we expand the node that is estimated to be closest to goal.
Here, we see that at each level, we have b nodes to choose from (since branching factor is b) and there are m such levels at max.
∴∴ The total no. of nodes to choose from = b×b×b×…m times=b^m
∴∴ Space complexity = O(b^m)
Hence option A is correct.