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Let marked price =4p, cost price=3p

Let discount percentage offered before it was sold =3q, profit(loss) percentage=4q.

Therefore (4p)-(4p)(3q)/100 = selling price................................................(1)

Assume it as a profit case then (selling price - 3p)/3p * 100 = 4q...............................................(2)

Now substitute 1 in 2 we get

{(4p) - (4p)(3q)/100 - 3p}/3p * 100 = 4q

{p(1- 12q/100)}/3p * 100 =4q

q = 100/24

In solving as no negative values are obtained our assumption of profit is true.......and finally value of 4q = 4*100/24 =50/3% profit

Option C is correct.

Let discount percentage offered before it was sold =3q, profit(loss) percentage=4q.

Therefore (4p)-(4p)(3q)/100 = selling price................................................(1)

Assume it as a profit case then (selling price - 3p)/3p * 100 = 4q...............................................(2)

Now substitute 1 in 2 we get

{(4p) - (4p)(3q)/100 - 3p}/3p * 100 = 4q

{p(1- 12q/100)}/3p * 100 =4q

q = 100/24

In solving as no negative values are obtained our assumption of profit is true.......and finally value of 4q = 4*100/24 =50/3% profit

Option C is correct.

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