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Lakshman Bhaiya asked Oct 24, 2018
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Suppose that a solution $(X,Y,Z)$ of the equation $X+Y+Z=20,$with $X,Y$ and $Z$ non-negative integers, is chosen at random.What is the probability that $X$ is divisible by $5?$ $A)\frac{1}{4}$ $B)\frac{5}{21}$ $C)\frac{2}{7}$ $D)\frac{3}{20}$
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[Discrete Maths] Counting ,Number of solutions to the equation
How many solutions are there to the equation x1 + x2 + x3 + x4 + x5 = 21, where xi , i = 1, 2, 3, 4, 5, is a nonnegative integer such that: 0 ≤ x1 ≤ 3 , 1 ≤ x2 < 4 and 15≤x3 ?
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