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+13 votes
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The rank of the matrix given below is:

$$\begin{bmatrix} 1 &4 &8 &7\\ 0 &0& 3 &0\\ 4 &2& 3 &1\\ 3 &12 &24 &2 \end{bmatrix}$$

  1. $3$
  2. $1$
  3. $2$
  4. $4$
asked in Linear Algebra by Veteran (59.7k points)
edited by | 1.3k views

1 Answer

+19 votes
Best answer

It's an non-singular 4x4 matrix, hence its rank is 4. A non-singular matrix has non-zero determinant.


(D) is correct option!

answered by Loyal (6.2k points)
edited by
+4

see this..

0
If you have a look at your solution again, you will find that you've jotted down the question wrong.The element at (2,4) is 21( not 2) which would make the first and second rows linearly dependent. Hence rank can't be 4.

It is 3.
0
If we take 2 then it would be rank =4 and if we consider 21 then rank would  be 3
Answer:

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