since genreally one micro insrctn take 1 clock cycle to complete, and each isrctn take 10 clocks and there total 258 insrctns, this means,
# of micro instrctns(control words)= 258*10 = 2580
in vertical μ progrmming, bits for control signal = log(#of conrol signals)= log129 = 8 //taking ceil
also, in μ progrmmng, each addr correspond to one control word, therefore # of addr bits = log2580= 12
and no mux selector lines are mentioned in qsn, so take it 0...control word will look like.
size of one conrol word = 20 bits + 4 bits(padding to make it next multiple of 8, because memory is by default byte aligned)
total size of control memory = 24*2580 bits = 7740 bytes.