given
Cache access time = 45ns
Main memory access time =750ns
hit ratio for read = 0.9
hit ratio for write = 1 { which means they are using simultaneous access}
avg time for read = hit in cache * access time of cache + miss in cache * MM access time
=0.9*45+0.1*750 =115.5ns
avg time for write = 1*750ns {directly accessing last level for write} = 750ns
avg time for read and write = 0.75*115.5 +0.25*750 =274.125