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The function represented by the Karnaugh map given below is

  1. $A.B$
  2. $AB+BC+CA$
  3. $\overline{B \oplus C}$
  4. $A.BC$
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The given K-map is not standard as after "01" we have "10" and two variables are changing for consecutive column. This means it is not safe to merge adjacent $1s.$ By converting the K-map to standard form we get

which gives

$BC + \bar B\bar C = B \text{ XNOR } C = B \odot C$

This can be represented as negation of $\text{XOR} = \overline{B \oplus C}$

Option C is correct.

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