linked list

Question

a

b

c

d

e

f / null

Assume the above is a singly linked list

first is pointing to a

what will be the output after this

struct node *p;

p = first->link->link->link;

p->link->link=first->link->link;

first->link->link->link=p->link;

printf("%c" , first->linl->link->link-link->data);

Comments

it will be 'c'

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How? I think it's 'd'.

Mind explaining a bit?

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In the first step p is updated to d node.Then e node's 'link' gets updated to point to c node.Then assignment of link from c to d node is skipped and c points to e. Then when we start from first i.e a again it skips 4 links it becomes a->b->c->e->c and data of c node is printed.(I hope i did correctly :) ) ...

Answer 1

Initially Linked list will be like 

After Statement 1 : p = first->link->link->link;

After Statement 2 : p->link->link=first->link->link;

After Statement 3 : first->link->link->link=p->link;

Now if we traverse  first->link->link->link-link->data; 'c' will be printed