Slow start

saumya mishra asked Nov 11, 2017

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jugnu1337 asked Dec 28, 2021

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slow start phase self doubt
when no of RTT is asked , i am confused when will start from 1 AND when will start from 2 rest part i known folow until thresold size and then increse with given MSS LET SUPPOSE THRESOLD 20 FOR EX ::: 1 2 4 8 16 20 22 24 26 OR 2 4 8 16 20 22 24 26 in ex 1 no of rtt is 9 while in ex 2 no of rtt is 8 can anyone tell me when we will start 1 and when we will start with 2

when no of RTT is asked ,i am confused when will start from 1 AND when will start from 2rest part i known folow until thresold size and then increse with given MSSLE...

jugnu1337

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jugnu1337 asked Dec 28, 2021

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Inspiron asked Jan 27, 2018

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Slow-Start
Consider the size of congestion window of a TCP connection be 36 KB when a timeout occurs. The round trip time of the connection is 200 μsec and the maximum segment size used is 2 KB. What is the time taken by the TCP connection to get back to 36 KB congestion window ... μsec D 2800 μsec Given answer is based on segments send but i think it should not be the case ! Please verify.

Consider the size of congestion window of a TCP connection be 36 KB when a timeout occurs. The round trip time of the connection is 200 μsec and the maximum segment size...

Inspiron

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Inspiron asked Jan 27, 2018

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Warlock lord asked Jan 16, 2018

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slow start
Suppose TCP's additive increase and multiplicative decrease algorithm is used as a congestion control algorithm. The slow start phase begins with 4 MSS and threshold at start of first transmission is 16 MSS. Assume that a time-out occurs during 6 th transmission ... ://gateoverflow.in/2156/gate2012_45 I'm not satisfied with the answer here. Shouldn't it start with 1 MSS again?

Suppose TCP’s additive increase and multiplicative decrease algorithm is used as a congestion control algorithm. The slow start phase begins with 4 MSS and threshold at...

Warlock lord

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Warlock lord asked Jan 16, 2018

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Tuhin Dutta asked Dec 19, 2017

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Confusion in #RTTs : Slow start-first full window
Suppose, size of a full window is 24 Kb. There is no congestion. 1 MSS = 2 Kb. RTT = 10 ms How long does it take to send the first full window? Approach 1) 2 | 4 | 8 | 16 | 24 = 4 RTTs =4 * 10 ms = 40ms Approach 2) 2 | 4 | 8 | 16 | 24 | = 5 RTTs = 5 * 10 ms = 50ms Which approach is correct?

Suppose,size of a full window is 24 Kb.There is no congestion.1 MSS = 2 Kb.RTT = 10 msHow long does it take to send the first full window?Approach 1) 2 | 4 | 8 | 16 | 24 ...

Tuhin Dutta

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Tuhin Dutta asked Dec 19, 2017

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Slow start

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