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Let there are 12 minterms in a function in which 8 minterms are covered by 2 Essential Prime Implicants. Each of the remaining 4 minterms have 2 Non- Essential Prime Implicants. Then the total number of minimal expressions is
Answer is 16.

Can anyone provide the solution to this problem.
closed as a duplicate of: Test Series
asked in Digital Logic by Junior (971 points)
closed by | 291 views

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