CSMA/CD with and without Collision

Question

A network with CSMA/CD protocol in the MAC layer is running at 1 Gbps over a 1 km cable with no repeaters. The signal speed in the cable is 2 x 10⁸ m/sec. The frame size for this network 10000 bits what is the total time requires to send this frame completely:-

1) when there is no collision in the channel.

2) when there is collision in the channel.

Comments

@Anu007 you mean to say "sense".

Any good reference?

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if there is no collison then :- T_t+T_p  

If collision:- T_t+C*2*T_p+T_p  

C:- no of colision...

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if there is no collison then :- T_t+T_p  (I think no need to wait for ack.)

 are acknowledgements there in CSMA/CD ?

Answer 1

probability for success is only one station transmit p max=1/e

 

so when collison occur time become 6.44Tp+Tt+2Tp

for first case why to check for collision if there is no collision so only Tp+Tt

Comments

@abhishek tiwary

Why you are using 6.44TP why not 5.44TP  or 5TP.

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6.44 is the factor which we get by probability 2Tp should be added u are right

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https://gateoverflow.in/97628/csma-cd

@abhishek tiwary

According to the above link the answer is just 6.44Tp+Tt  , which one is correct?  Will the extra 2*Tp term be added?