$J _{a} = JQ_{a}' + K'Q_{a} = Q_{a}' + Q_{b}$
Similarly,
$J _{b} = JQ_{b}' + K'Q_{b} = Q_{c}.Q_{b}'$
and,
$J _{c} = JQ_{c}' + K'Q_{c} = Q_{c}' + Q_{a}$
| $Q_{a}$(Present State) |
$Q_{b}$(Present State) |
$Q_{c}$ (Present State) |
$Q_{a}$ (Next State)= $Q_{a}'$(PS) + $Q_{b}$ |
$Q_{b}$ (Next State)= $Q_{c}$(PS) .$Q_{b}'$ |
$Q_{a}$ (Next State)= $Q_{c}'$(PS) + $Q_{a}$ |
| 0 |
0 |
0 |
1 |
0 |
1 |
| 1 |
0 |
1 |
0 |
1 |
1 |
| 0 |
1 |
1 |
1 |
0 |
0 |
| 1 |
0 |
0 |
0 |
0 |
1 |
| 0 |
0 |
1 |
1 |
1 |
0 |
| 1 |
1 |
0 |
1 |
0 |
1 |
*PS = Present State
Hence, from the table above, we can infer that the state changes are $S_{5}\rightarrow$$S_{3}\rightarrow$ $S_{4}\rightarrow $$S_{1}\rightarrow$ $S_{6}\rightarrow $$S_{5}$.
So, the answer is A)
