It is required to divide the 2n members of a club into n disjoint teams of 2 members each. The teams are not labelled. The number of ways in which this can be done is:
(A) (2n)! / 2^{n}
(B) (2n)! / n!
(C) (2n)! / 2^{n} · n!
(D) n! / 2
Gatecse