Combinatorics closed

Question

It is required to divide the 2n members of a club into n disjoint teams of 2 members each. The teams are not labelled. The number of ways in which this can be done is:

	(A) (2n)! / 2n
	(B) (2n)! / n!
	(C) (2n)! / 2n · n!
	(D) n! / 2