0 votes 0 votes Rakshit Gupta asked Nov 15, 2017 Rakshit Gupta 1.1k views answer comment Share Follow See all 3 Comments See all 3 3 Comments reply santhoshdevulapally commented Nov 16, 2017 i edited by santhoshdevulapally Nov 16, 2017 reply Follow Share y=$\lim_{x->0}$$(3cosx+2sin3x)^{1/x}$ First remove power so apply log on both sides $log_{e}^{y}$= $\lim_{x->0}$log(3cosx+2sin3x)/x $log_{e}^{y}$ =infinity y=e^ infinity y =infinity 0 votes 0 votes Rakshit Gupta commented Nov 16, 2017 reply Follow Share L hospital rule can only be apply on 0/0 or infinity/infinity form 0 votes 0 votes joshi_nitish commented Nov 16, 2017 reply Follow Share limit will tend to ∞ lim x->0 (3cosx + 2sin3x)1/x = 3∞ -> ∞ 0 votes 0 votes Please log in or register to add a comment.