1 votes 1 votes L1=(ab)* L2=a*b* L=L1 intersection L2 number of states in MFA that accepts L is? Theory of Computation theory-of-computation + – aaru14 asked Nov 15, 2017 aaru14 488 views answer comment Share Follow See all 7 Comments See all 7 7 Comments reply Show 4 previous comments Anu007 commented Nov 15, 2017 reply Follow Share yes in dfa 0 votes 0 votes Shivam Chauhan commented Nov 16, 2017 reply Follow Share MFA is askes MInimal Finite Automata. L={ε,ab} only two states needed with NFA. 0 votes 0 votes Anu007 commented Nov 16, 2017 reply Follow Share Draw it. 0 votes 0 votes Please log in or register to add a comment.
Best answer 0 votes 0 votes L1 ={ epsilon , ab, abab, ababab......} L2={epsilon, a,aa,aaa,....b,bb,bbb,....ab, aabbb....} L1 intersection L2 ={epsilon,ab} MFA Required three states to accept above language. Akash Mittal answered Nov 15, 2017 • selected Nov 16, 2017 by Shivam Chauhan Akash Mittal comment Share Follow See all 2 Comments See all 2 2 Comments reply Aashish S commented Nov 16, 2017 reply Follow Share what abt dead state 0 votes 0 votes aaru14 commented Nov 16, 2017 reply Follow Share if it is union between them then?? 0 votes 0 votes Please log in or register to add a comment.