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L1=(ab)*

L2=a*b*

L=L1 intersection L2

number of states in MFA that accepts L is?

1 Answer

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L1 ={ epsilon , ab, abab, ababab......}

L2={epsilon, a,aa,aaa,....b,bb,bbb,....ab, aabbb....}

L1 intersection L2 ={epsilon,ab}

MFA Required three states to accept above language.

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