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Consider two nodes A and B on the same Ethernet segment, and suppose the propagation delay between the two nodes is 300 bit times. Suppose at time both nodes A and B begin to transmit a frame. Assume both nodes transmit a 60 bit jam signal after detecting a collision. For 10^7 bits per set Ethernet, find the time at which both nodes A and B sense an idle channel? [in microseconds]( Marks: 0.00 )

  1.   22.5 micro sec
  2.   27.5 micro sec
  3.   72.5 micro sec
  4.   66 micro sec

2 Answers

2 votes
2 votes

Given BW = 10bit/sec which means

1sec ------- 107 bit

1bit --------- 10-7 sec

It is given "the propagation delay between the two nodes is 300 bit times"

PD = Propogation delay

PD = 300 * 10-7 sec

PD = 30 micro sec.

Now, Collision Occur between 0* PD to 1* PD

And, Collision Detected between 0*PD to 2*PD

Suppose in worst case stations detected collision in 2PD = 2*30 msec = 60 msec.

And after detecting the collision both stations send 60 bit jam signal, in terms of time it is equal to 60 * 10-7 sec = 6 micro sec.

Total time = 60 micro sec + 6 micro sec = 66 micro sec.

And after all these both stations sense the channel is idle at 66 micro sec.

2 votes
2 votes

This can be solution.

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