combinatoric

Question

No of ways to distribute 6 different gifts to 2 student from total 4 student ?

my approach ... distinct to distinct ... am getting 378 , given ans is 384 ... they permuted ..is this correct  ...?

Comments

I am not getting your approach. But you can do like this-

Selecting 2 students out of 4 which is C(4,2) and then distribute among them 6 different gift.

Now for this distribution, you can use the Binomial theorem that is (a+b)⁶  which will give 64. Total there are 384 ways.

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permuted because each gift is unique so its not like any two gift since every pair of gift is unique .

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ok thanks ... i have to check my solution again ..

Answer 1

First select 2 student from 4 students that would be 4C2 = 6 pairs

this distribution is Distinct to Distinct , we can see as function from object {A} to students {B}

Total no of function from A-->B = |B|^|A|

                                                            =2^6

total no. of student pairs are 6, every pair has 2^6 ways

hence , total no of distribution = 6*2^6