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let y= lim x-->a f(x)g(x)

if by putting limit we got 1inf 

then y = lim x-->a g(x) * {f(x)-1}

now see problem

f(x) = 1-(1/2n)) and g(x) = 2n and by putting limit we got 1inf  type

lim x-->inf 2n* {(1-(1/2n))-1}

lim x-->inf 2n* {-1/2n}

= e-2

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