1 votes 1 votes atul_21 asked Nov 19, 2017 atul_21 1.4k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 2 votes 2 votes t1-->t2 {w1B--r2B is c conflict} only one serial schedule possible. for t2 -->t1 {w2A -- r1A is a conflict} only 1 serial schedule possible. TOTAL=2 raviyogi answered Nov 19, 2017 • selected Nov 19, 2017 by atul_21 raviyogi comment Share Follow See all 8 Comments See all 8 8 Comments reply Show 5 previous comments Manu Thakur commented Nov 19, 2017 reply Follow Share @ravi i understood your point. due to conflict pairs concurrency is not possible fot these two transactions. there are only 2 possible schedules first execute T1 completely followed by T2 (or) First execute t2 completely followed by T1. I didn't get the question itself, "how many concurrent schedules are conflict serializable" but there is no concurrency possible here, right? 1 votes 1 votes atul_21 commented Nov 19, 2017 reply Follow Share Thank you @raviyogi 0 votes 0 votes raviyogi commented Nov 19, 2017 reply Follow Share serial schedule are always serializable. 0 votes 0 votes Please log in or register to add a comment.