Cache size = 8byte
Block size = 2byte
#f lines = Cache size/Block size
=> 8/2= 4 lines
#f sets (S)= #f lines / associativity
=> 4/2 = 2 sets
Using LRU :
mapping technique in set associativity => k mod S = i {k=memory block no.}
only memory block "2" will hit
total no of hit =1
