pointers

Question

#include<stdio.h>

int main()

{

    int arr[] = {10, 20, 30, 40, 50, 60};

    int *ptr1 = arr;

    int *ptr2 = arr + 5;

    printf("Number of bytes between two pointers are: %d", 

                              (char*)ptr2 - (char*) ptr1);

    return 0;

}

Please explain the above code

Comments

10 for 2B int

Answer 1

Elements	10	20	30	40	50	60
Address	1000	1004	1008	1012	1016	1020

Assuming size of int = 4byte and size of char = 1byte

ptr1 =1000

ptr2= 1000+5 {skipping 5 elements of size 4byte each}

=> ptr2 =1020

type casting is done here into char

(char*)ptr2 - (char*) ptr1);

1020-1000=20/size of char

o/p: 20