TLB tag bits

Question

Answer 1

Answer : TLB tags bits =16.

Explanation -

Actually TLB is cache memory.

Hence this problem may be considered as in the subject CO

Here Page size = 16KB = 2¹⁴ B. hence to represent all pages we need 14 bits.

TLB having 256 entries (i.e lines)

It uses 4 way set associativity, hence number of sets = 256/4 = 64 = 2⁶ (Though it is already given, but this is actual method which will be helpful while solving other problems.

Now in set associative mapping

Virtual address is distributed as

Tag

set number

Block/page offset

Virtual address = 36 bit.

set number = bits required for representing sets = 6

Block/page offset = bits required for representing pages = 14

Hence Tag = VA bits - (set number + page offset)

Tag bits = 36 - (6+14)

Tag bits = 36 - 20 = 16

Comments

Thank you so much @Ashwin