4 votes 4 votes The values of P,Q,R, if 47Q80 is the 10's c complement of RPRP0 are a)4, 3, 2 b) 5,4,4 c)3,4,5 d)2,4,5 Digital Logic number-representation + – Sanjay Sharma asked Nov 22, 2017 • retagged Nov 22, 2017 by Arjun Sanjay Sharma 2.7k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 2 votes 2 votes Ans is option D. 10's compliment of base 10 number X with n digits = 10n - X here, n = 5, X = RPRP0 hence 100000 - RPRP0 = 47Q80 from unit place : 0-0 = 0 then, 10 - P = 8. Hence P =2. then, 9 - R = Q ( compute this later) ...(1) then 9 - P = 7. Confirmation of P =2. then, 9 - R = 4. hence R =5. again from eq (1), 9-R = Q => 9-5 = 4, hence Q =4. P = 2, Q=4, R =5 Ashwin Kulkarni answered Nov 22, 2017 • selected Nov 22, 2017 by Sanjay Sharma Ashwin Kulkarni comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes 100000-47Q80=RPRP0 now 100000=47Q80+RPRP0 P+8 SHOULD HAVE 0 IN THE UNIT PLACE ONLY 3 IS MATCHING SO P=2; NOW P+8 WILL GIVE A CARRY SO R+Q+1 SHOULD HAVE 0 IN UNIT PLACE =4+5+1=10 NOW 100000=47480+52520 Red_devil answered Nov 22, 2017 Red_devil comment Share Follow See all 0 reply Please log in or register to add a comment.