0 votes 0 votes closed with the note: Correct answer is 2. I solved it. The number of linearly independent eigenvectors of matrix A= $\begin{pmatrix} 2 &1 & 0\\ 0& 2 &0 \\ 0& 0 & 3 \end{pmatrix}$ Linear Algebra me-gate2016 linear-algebra + – Ayush Upadhyaya asked Nov 24, 2017 closed Nov 24, 2017 by Ayush Upadhyaya Ayush Upadhyaya 1.4k views comment Share Follow See all 3 Comments See all 3 3 Comments reply Ayush Upadhyaya commented Nov 24, 2017 reply Follow Share My answer is coming to be 3. Could anyone confirm? 0 votes 0 votes just_bhavana commented Nov 25, 2017 reply Follow Share Eigen values are 2, 2, 3 and since 2 is repeated, only 2 linearly independent eigenvectors are possible 0 votes 0 votes Debapaul commented Apr 29, 2020 reply Follow Share @just_bhavana This has no meaning that number of distinct eigen values= number of linearly independent eigen vectos. Consider this example and tell me the number of linearly independent eigen vector. $A=\begin{pmatrix} 2&0 \\ 0&2 \end{pmatrix}$ 0 votes 0 votes Please log in or register to add a comment.