2 votes 2 votes closed with the note: Got the clarifications in comments The efficiency of a Go-Back-N protocol is $\eta = \frac{N}{1+ 2 *\frac{Propogation Delay}{Transmission Delay}}$ In this equation what is the exact value of N. Is it the one given in Go-Back-N or (2N-1). Computer Networks computer-networks go-back-n sliding-window + – sumit chakraborty asked Nov 26, 2017 • closed Nov 26, 2017 by sumit chakraborty sumit chakraborty 1.1k views comment Share Follow See all 3 Comments See all 3 3 Comments reply Hemant Parihar commented Nov 26, 2017 reply Follow Share It is the one given in GO-Back-N. 2 votes 2 votes sumit chakraborty commented Nov 26, 2017 reply Follow Share Thanks for the clarification. I was seeing one of the question where the Go-Back-7 was given and efficiency was calculated by $\frac{127}{1+2*\frac{Propagation Delay}{Transmission Time}}$. Instead it should have been $\frac{7}{1+2*\frac{Propagation Delay}{Transmission Time}}$. Right ? 0 votes 0 votes Habibkhan commented Nov 26, 2017 reply Follow Share Yes it should be N only..N refers to the window size i,e, the number of frames that can be transmitted in 1 go.. 5 votes 5 votes Please log in or register to add a comment.
