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in Databases by Active (3.2k points) | 123 views

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+1 vote
4 tables created ..

here candidate key is AC...

so A->B fails to be in bcnf we divide it in table which B->D fails so we divide in AB and BD...

C->E again fails so we divide ....CE is table...

lastly to maintain KEYS ...we have AC...

so totals tables are

by Boss (11k points)
4 tables will be created for bcnf decomposition.... AC,  AB, CE, BC..... these will be lossless as well as dependency preserving.... If it would had been asked for 2nf... Then only 3 tables will be created... AC, ABD, CE
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