If we are given preorder and inorder then we can generate a unique binary tree. But in question we are given only in order.
So, what we do now - we take inorder & options one by one (as preorder) and try to make unique binary tree from them.
We will observe that options A & C will fail.
Only B & D can generate unique trees. so, options (B) & (D) are correct
Trees will look like this as given by Pranay Datta 1