In these type of questions, i.e. when you raise a number to some power, find the pattern of unit digit and then solve.
(1) $39^{11} - 32^{11}$
For $39^{11}$ : Unit digit of 39 is 9, and thus unit digits of its powers will be 9,1,9,1,... So $39^{11}$ ends in 9.
For $32^{11}$ : Unit digit of 32 is 2, and thus unit digits of its powers will be 2,4,8,6,2 (and then pattern continues). So $32^{11}$ ends in 8.
So unit digit of $39^{11} - 32^{11} = 9-8 = 1$
Solve second question similarly and we get 5 + 9 - 4 = 0 for unit digit.