Given Plain text (m)=5, P=3, Q=11
where P and Q are two prime integer
n=P*Q
n=3*11=33
Z=(P-1)*(Q-1)
Z=(3-1)*(11-1)=20
Now selecting the public key(i.e encryption key) E such that it is not a factor of (P-1) and (Q-1)
say E=3
Now selecting the private key (i.e the decryption key) D such that the following equation is true:
(D*E) mod Z =1
Say D=7
(7*3) mod 20 =1
For encryption calculating the cipher text (CT) from the plain text (PT) is as follows:
CT = (PT)^E mod n
CT = 5^3 mod 33
Cipher Text =26
Now Sender will send this cipher text (26) to the receiver
For decryption calculating the plain text PT from the cipher text CT as follows:
PT = (CT)^D mod n
= (26^7) mod 33
= 5