permutations

Question

given nine elements A,B,C,D,E,F,G,H,I.How many ways we can arrange them such that it must follow order 1)A-C-D-E,2)  E-H-I (Meaning of 2) is h should not come before e and i should not come before e,h)

Comments

Basic Order

_ A _ C _ D _ E _ H _ I _   remaining element B , F , G  they can place any where in this 7 place

Total= 7*7*7 = 343 Way

B, F, G can arrange in 3!=6 way

 

Total =343*6 =2058 way

Please tell me if I am Wrong

Answer 1

We just have to select position

First select position for A,C,D,E then E,H,I then B,F $^{9}C_{4}*^{5}C_{3}*2$

or you can select position in any order answer will be same