Total Number of combinations possible at 7 places = 67
Out of 6 numbers, 1 will repeat.
Thus, a number can be chosen in 6 ways and it will appear at 2 positions which can be chosen in 7C2 ways.
Rest of the 5 places (2 filled by a number) can be filled in 5! ways.
Thus probability = ( 6 * 7C2 * 5! ) / (67)
Answer is B