Answer: Given that at the time of Time Out, Congestion Window Size
is $32\;\textsf{KB}$ and RTT $= 100\;\text{ms}$,
When Time Out occurs, for the next round of Slow Start,
Threshold $= \dfrac{\text{size of congestion window}}{2}$ ,
Threshold $= 16\;\textsf{KB}$
Suppose we have a slow start $\Rightarrow2\;\textsf{KB} \mid 4\;\textsf{KB} \mid 8\;\textsf{KB} \mid 16\;\textsf{KB}$
(As the threshold is reached, Additive increase starts)
$\mid 18\;\textsf{KB} \mid 20\;\textsf{KB} \mid 22\;\textsf{KB} \mid 24\;\textsf{KB} \mid 26\;\text{KB} \mid 28\;\textsf{KB} \mid 30\;\textsf{KB} \mid 32\;\textsf{KB}$
Here | (vertical line) is representing RTT so the total number of vertical lines is
$11\times 100\;\text{ms} = 1100\;\text{msec}$ and so this is the answer.