packet size including header=1800B and Packet size excluding header=1800-20(It is minimum header size as given in problem)=1780Byte
Now This packet is going to enter a network in which the MTU (Data+header size at the Data link layer) is 500Byte.
Therefore,
Data size excluding header at this network will be=480 Byte
Number of Fragments(done by the router)=Ceil(1780/480)=4.
First Fragment Size |
Second Fragment Size |
Third Fragment Size |
Fourth Fragment Size |
(480+20)->It is also known as payload |
480+20)->It is also known as payload |
480+20)->It is also known as payload |
(340+20) |
|
|
|
This is our answer which is asked. |
Happy Learning