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Suppose a packet of length 1800 bytes with minimum header size enter a local area network with MTU (Maximum transfer unit ) of 500 bytes, then how many fragments will be generated from the packet and what is size of the payload of the last packet ?
asked in Computer Networks by Active (3.2k points) | 213 views
+1
4, 340
+1
Yeah since it's "payload" it must be 340. Just wanted to confirm. The test series concluded to be 4,360. Thanks.
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offset would be 180 right?
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how are you getting 340?
min header size is 20, so 480 can be max payload.

1800 - 3*480 = 360 will be payload of final packet.

Am I doing something wrong?
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@ Rishabh 1780 - 3*480
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oh..blunderous mistake. Thanks for correcting.
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Warlock lord

will u please explain ...why 1780 ....as if we talk about frame size that is going to be 18 bytes.....

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But @hs_yadav Sir  "a packet of length 1800 bytes with minimum header size" (20B ) thus payload becomes 1780.

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Right
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4,360

1 Answer

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Answer 4,360

answered by Active (3k points)

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