$S \rightarrow aAbB \ \ \ \ \ \ \ ..... 1 $
$S \rightarrow bAaB \ \ \ \ \ \ \ ..... 2 $
$S \rightarrow \epsilon \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ..... 3 $
$A \rightarrow S \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ..... 4 $
$B \rightarrow S \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ..... 5 $
FIRST |
FOLLOW |
NON-TERMINAL |
a |
b |
$ |
$\{ a, b, \epsilon \}$ |
$\{ \$,b,a \}$ |
S |
1 / 3 |
2 / 3 |
3 |
$\{ a, b, \epsilon \}$ |
$\{b,a \}$ |
A |
4 / 4 |
4 / 4 |
|
$\{ a, b, \epsilon \}$ |
$\{ \$,b,a \}$ |
B |
5 / 5 |
5 / 5 |
5 |
$$\begin{array}{|l|l|l|l|l|}\hline \textbf{FIRST}&\textbf{FOLLOW}&\textbf{NON-TERMINAL}&\textbf{a}&\textbf{b}&\textbf{\$}\\\hline \{a,b,\epsilon\}&\{\$,b,a\}&\text{S}&1/3&2/3&3\\\hline \{a,b,\epsilon\}&\{b,a\}&\text{A}&4/4&4/4&\\\hline \{a,b,\epsilon\}&\{\$,b,a\}&\text{B}&5/5&5/5&5\\\hline\end{array}$$
There are 2 entries with multiple different productions which results in First/First conflict.
however there are 6 multiple entries in the table.