If we consider the grammar to be LR(0) there would be S-R conflict in the given canonical form.
Suppose that the present state is I0 and on transition on > it goes to I1 state.
S->L.>R --production number :1 (on correction of existing question)
Q->R. ---production number:2
In LR(0) reduced move will be placed in entire row.(under terminal columns)
Here we cant determine SLR(1) paring table as the follow of Q is unknow so we dont know how to place the reduced move.
Suppose we go with the given question(on transition on <)
it wont go to any state so no S-R or R-R as that terminal (<) is not present in the canonical set of LR(0).