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IIs the answer 4TB?

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4TB is answer when you ignore 8 direct and 4 double indirect

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Answer 1

Answer is approximately 4 TB

Disk block size = 4KB = 2¹²B

Block address size = 32 bits = 4B = 2²B

Hence number of pointers in a block = 4KB/4B = 1K = 2¹⁰ B

Hence

direct block size = 4KB

single indirect blocks size = pointers * block size = 2¹⁰ * 4KB

double indirect blocks size = pointers * pointers *  block size = 2¹⁰ * 2¹⁰ * 4KB

triple indirect blocks size = pointers * pointers *  pointers * block size = 2¹⁰ * 2¹⁰ * 2¹⁰ * 4KB

Total file size = 8 direct + 2 single indirect  + 4 double indirect + 1 triple indirect.

(8 + 2* 2¹⁰ + 4*2¹⁰ *2¹⁰ + 2¹⁰ *2¹⁰ *2¹⁰ ) * 4KB

By ignoring direct single and double indirect (size is comparatively small) we get => 2³⁰B * 4KB = 4 * 2⁴⁰B = 4TB